4n^2=-28n-49

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Solution for 4n^2=-28n-49 equation: 



4n^2=-28n-49

We move all terms to the left:

4n^2-(-28n-49)=0

We get rid of parentheses

4n^2+28n+49=0

a = 4; b = 28; c = +49;
Δ = b2-4ac
Δ = 282-4·4·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-28}{8}=-3+1/2$

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